Mass hanging in a boxcar accelerating

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A 1 kg mass hangs in a boxcar accelerating at 7 m/s², and the tension in the rope is questioned. The initial calculations yield a tension of 71 N, but the expected answer is 12 N. The discussion emphasizes breaking down the forces into x and y components using F=ma. A suggestion is made to provide a free body diagram for clarity, and a check on the mass value used in the x-component calculation is recommended. The key issue lies in correctly applying the equations for tension in an accelerating frame.
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1. Homework Statement
A mass of 1 kg hangs inside a boxcar of a train. If the train accelerates at 7 m/s^2, what is the approximate tension in the rope?

A: 12 N

Homework Equations


F=ma

The Attempt at a Solution


I originally thought of doing this problem as pythagorean theorem, but I wanted to work out the x and y components for practice. Breaking up the components:
ΣFy=may
Ty-mg = may
Ty=10N

ΣFx=max
Tx=10*7
Tx=70N

Thus, T2=102+702
T=71 N

The problem sets it up just like I do but get 12 N for their answer:
T2=ma2+mg2

What am I doing wrong? Thanks in advance!
 
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brake4country said:
1. Homework Statement
A mass of 1 kg hangs inside a boxcar of a train. If the train accelerates at 7 m/s^2, what is the approximate tension in the rope?

A: 12 N

Homework Equations


F=ma

The Attempt at a Solution


I originally thought of doing this problem as pythagorean theorem, but I wanted to work out the x and y components for practice. Breaking up the components:
ΣFy=may
Ty-mg = may
Ty=10N

ΣFx=max
Tx=10*7
Tx=70N

Thus, T2=102+702
T=71 N

The problem sets it up just like I do but get 12 N for their answer:
T2=ma2+mg2

What am I doing wrong? Thanks in advance!
Can you show us your free body diagram for this problem? That is generally the first/best step on these problems. :smile:
 
brake4country said:
Breaking up the components:
ΣFy=may
Ty-mg = may
Ty=10N

ΣFx=max
Tx=10*7 ⇐
Tx=70N
Check the mass value used for the calculation of the x-component.
 
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