Mass of Steam Needed for 1kg of Ice to Yield 20°C Water

AI Thread Summary
To determine the mass of steam needed to convert 1 kg of ice at 0°C to liquid water at 20°C, the latent heat of fusion (3.3 x 10^5 J/kg) is used in the calculation. The equation involves the heat required to melt the ice and raise the temperature of the resulting water. It is essential to clarify which mass variable corresponds to steam in the equation, as both sides contain the variable "m." By solving for the mass of steam, the required energy transfer can be accurately calculated. This approach ensures a clear understanding of the thermal dynamics involved in the phase change and temperature increase.
heelp
Messages
23
Reaction score
0
what mass of steam at 100 c must be added to 1.ookg of ice to yeild liquid water 20c ?

this is what I have so for c*m* displacement of temperature =m *L
 
Physics news on Phys.org
You should know L (which I believe is 3.3 x 10^5 J/kg). Which is the Latent Heat of Fusion. You are given the mass of ice, change in temperature. Just solve for the second m in your equation. Which I'm assuming in the mass of the steam. When you have two of the same variables on each side of the equal sign, it looks confusing. Please denote "m of what".
 
Last edited:
m is the mass
 
I know that m is the mass. But you have an m on each side of the equal sign. What I'm asking you to state is the "mass of what". In your equation just solve for the m that relates to steam.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

How much ice to cool down this water?
Replies
17
Views
5K
Calorimetry: Finding mass of ice, water, steam left
Replies
1
Views
4K
Mixing water and ice
Replies
12
Views
864
Finding the Value of M in a Physics Homework Problem
Replies
12
Views
2K
1 kg of ice at -20°C is mixed with 1kg steam at 200°C......
Replies
9
Views
7K
Heat Transfer. Ice and steam in a container (easy)
Replies
2
Views
4K
I try to solve a thermodynamics problem on heat transfer
Replies
3
Views
2K
Confusion about whether to use the specific heat of water or ice
Replies
4
Views
2K
Heat exchange in an isolated system
Replies
3
Views
2K
How Do You Calculate the Final Mass of Water in a Calorimetry Experiment?
Replies
3
Views
2K

Hot Threads

Recent Insights

Back
Top