Mass of Surface: Find Double Integral over S

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Homework Statement


If the mass per unit area of a surface is given by rho = x*y, find the mass
double integral over S of x*y dS if S is the part of the cylinder x^2 + z^2 = 9 which is in the first octant and contained within the cylinder x^2 + y^2 = 4.

Homework Equations


Above.

The Attempt at a Solution


I can visualize what the shape looks like, but I'm not sure how to define the bounds of integration based on the shape described.
 
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does anyone have any ideas? help would be greatly appreciated.
 
Make sure you're visualizing the shape from a useful viewpoint. I suggest looking "from above." In other words, draw the xy-plane as usual on your paper, position your eye directly above the origin, and imagine the z-axis pointing straight out at your eye. Shade the region in the xy-plane that is covered by the surface.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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