Mass on 2 ropes, looking for tension

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The discussion focuses on calculating the tension in two ropes supporting a 3.3 kg block, with angles of 40 degrees and 30 degrees from the horizontal. Participants emphasize the importance of resolving the tension forces into their x and y components using trigonometric functions. The equations derived include T2x - T1x = 0 for the x-direction and T2y + T1y = mg for the y-direction, where mg is calculated as 32.34 N. There is a consensus on needing to substitute the cosine and sine values for the angles to solve the system of equations. The conversation highlights the correct approach to solving for the tensions T1 and T2, ensuring all components are accounted for.
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Homework Statement



A block of mass 3.3 kg is suspended by two ropes as shown in the picture below.
The angle that the left rope makes with the horizontal is q= 40 degrees.
The angle that the right rope makes with the horizontal is q= 30 degrees.

What is the tension in the left rope?
A. T1 = 16.5 N

B. T1= 22.4 N

C. T1= 29.8 N
What is the tension in the right rope?

A. T2 = 26.4 N

B. T2 = 30.2 N

C. T2 = 33.1 N

Homework Equations



F=ma

The Attempt at a Solution


I separated each of the T vectors into their x and y components and was planning on using the sine of the given angles in order to solve for the tension. I keep coming up with something like T=mg/sin30, but the answer that I get for this is nowhere near any of the options. I know I am probably missing something so simple, but I can't for the life of me figure out what it is. Please help!
 
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You have to look at the sum of the tension vector components in both directions. Write down your 2 equations (one in the x direction and the other in the y direction). What do you get?
 
In the x direction I came up with T2x-T1x=0
In the y direction I came up with T2y+T1y=mg
I found mg=32.34
Not sure where to go from here though.
 
Your equations are correct. Now just solve for the components of the tension forces based on the given angles as a function of the tension and angle. You know that T1 makes an angle of 40 degrees with the horixontal, so T1x = T1*?

Etcetera.
 
Ok, so T1x=T1*cos40? The problem with this is that I end up with 2 variables and I'm not sure how to solve for either one of them with the given info. It seems like the 32.34 should be worked in somewhere but being that it's the sum of T2y and T1y, I'm not sure how to apply it.
 
Cos 40, sin 40,cos 30, sin 30...they all have numerical values..plug them in...then solve 2 equations with 2 unknowns (T1 and T2) by a method of your choosing.
 
Thanks for the help! Still working out the details but it is good to know I'm on the right track.
 
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