Mass on spring rotates - what happens?

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When a heavy object is hung on a spring and the spring is rotated, the dynamics involve centripetal force and the spring's tension. The centripetal force required for circular motion is given by mv^2/r, where m is mass, v is velocity, and r is the radius of rotation. The vertical component of the spring force balances the weight of the object. To find the total spring force, one must calculate the resultant of the horizontal and vertical components. Finally, Hooke's law can be applied to determine the extension of the spring based on the resultant force.
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hi,
what happens, when I hand on a spring a heavy object and then we'll rotate the spring? I've tried to write down some maths for it but I don't know anyway...
 
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ambroa said:
hi,
what happens, when I hand on a spring a heavy object and then we'll rotate the spring? I've tried to write down some maths for it but I don't know anyway...
It's the same as rotating the object hung on a rope: if swung in a horizontal circle at constant speed, v, the centripetal force is mv^2/r, which is the horizontal component of the spring force, and the verticlal force component of the spring force is the weight of the object. Once you calculate the resultant spring force, use Hooke's law to determimne its extension.
 

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