What Is Stability in the Context of the Hill Equation for a Mass-Spring System?

Drokz
Messages
3
Reaction score
0
When trying to solve a problem I arrive at the following equation of motion / Hill equation:

\frac{d^{2}y}{dx^2} + \frac{4 k_0}{m w^2} cos(2x)y = 0

There exists a value x_0 such that for all x>x_0 the motion is stable.

I actually don't know what is meant by this 'stability'. Can someone help, please?

Thanks, Drokz
 
Physics news on Phys.org
I've usually seen Hill's equation with omega^2, not omega^(-2). Is this a typo?
 
I don't think it is a typo. Omega is just a constant here, I think.
 
Ok. Solutions are products of exponential terms and periodic functions, so your stability condition is needed to keep the exponential parts of the solutions bounded. Do you have access to a reference on Mathieu functions like Whittaker and Watson, or Erdelyi's Higher Transcendental Functions? The latter one has a clear discussion of the stable and unstable solution regions (p. 101 vol. 3).
 
##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top