Masses on Pullies, equal weights on both sides but still rotating

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In a double Atwood machine with a mass of 4m suspended from a pulley, the system accelerates downward at g/7 when released. Despite having equal weights on both sides of the top pulley, it rotates due to the unequal forces acting on the second pulley, where mass m moves upward while mass 3m moves downward. The net force on the second pulley, calculated as the difference between the forces on the two sides, results in a greater force on the 4m side, causing the top pulley to rotate. This demonstrates that even balanced weights can lead to motion if the forces acting on them are not equal. The analysis reveals the complexities of pulley systems and the importance of understanding net forces in mechanics.
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Homework Statement


Consider a double Atwood machine constructed as follows: A mass 4m is suspended from a string that passes over a massless pulley on frictionless bearings. The other end of this string supports as second similar pulley, over which passes a second string supporting a mass of 3m at one end and m at the other. Find the acceleration of the mass 4m when the system is released.

Explain why the top pulley rotates even though it carries equal eights on each side.


Homework Equations





The Attempt at a Solution


The mass 4m accelerates downwards with an acceleration of g/7.

Can anyone explain why, though, the pulley rotates at all, since it has equal weights on both sides?
 
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In the second pulley, m is going up and 3 m is going down. If net force on m is f1 and that on 3m is f2, the net force on the second pulley is f2 - f1. And f1 and f2 are not the weights. So 4mg on the right is greater than f2 - f1. Hence the first pulley rotates.
 
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