Mastering Limit Problems: Homework Statement & Solution | 65 Characters

  • Thread starter Thread starter screamtrumpet
  • Start date Start date
  • Tags Tags
    Limit
screamtrumpet
Messages
16
Reaction score
0

Homework Statement


lim
x>b (b-x)/sqr rootx-sqr root b





The Attempt at a Solution


I multilplied the top and bottom by b+x and found b-x^s on the top and x-b on the bottom
 
Physics news on Phys.org
Try multiplying through by the conjugate of \sqrt{x}-\sqrt{b}...
 
so would that be square root x plus square root b?
 
Yes it should be.
 
after factoring and simplifying i got my answer to be 2b
 
screamtrumpet said:
after factoring and simplifying i got my answer to be 2b

Not right. If you would show how you got there someone might be able to tell you why it's wrong.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top