Mastering Simple Algebra with Helpful Tips and Examples

[DB]

(another) simple algebra question

\frac{300}{5v_w}+\frac{300}{3v_w}=8

can some1 give me a hand on the algebra here? thanks

 

[TD]

Multiply both sides with v_w to get:

\frac{{300}}<br /> {{5v_w }} + \frac{{300}}<br /> {{3v_w }} = 8 \Leftrightarrow v_w \left( {\frac{{300}}<br /> {{5v_w }} + \frac{{300}}<br /> {{3v_w }}} \right) = 8v_w \Leftrightarrow \frac{{300}}<br /> {5} + \frac{{300}}<br /> {3} = 8v_w

 

[DB]

okay but i only multiply the numerators by v_w? otherwise i would get v_w^2 in the denominators...right?

 

[DB]

i get 20 btw

 

[TD]

Yes, that wouldn't help anything. You just multiply both sides with it, and when you multiply a fraction with a factor, it's always in the nominator. c * a/b = ca/b.

You do this to get rid of the v_w in the denominators since you can cancel them out when they're also in the numerators.

i get 20 btw

Correct You can check it by plugging it in the initial equation.

 

[DB]

thanks TD, i see it perfectly now

 

[TD]

No problem, glad I could help

 

[DB]

just out of curiosity...how would i approach:
\frac{300}{5v_w+10}+\frac{300}{3v_w}=8
?
thanks

 

[VietDao29]

You can try simplify the equation a bit:
\frac{300}{5v_w + 10} + \frac{300}{3v_w} = 8
\Leftrightarrow \frac{60}{v_w + 2} + \frac{100}{v_w} = 8
Then, you can try multiplying both sides with v_w(v_w + 2) to get rid of the denominator. And you will have:
60v_w + 100(v_w + 2) = 8v_w(v_w + 2)
You can rearrange a bit, and you will have a quadratic equation.
Can you go from here?
Viet Dao,