Mastering the V and M Diagram: A Comprehensive Guide for Success

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SUMMARY

The discussion focuses on mastering the V and M diagrams in structural analysis, specifically addressing the calculation of bending moments and shear stresses in beams. Key concepts include the moment of inertia (I), the first moment of area (Q), and the polar moment of inertia (J). The participant clarifies that the bending stress is inversely proportional to the second moment of area, and that axial loads and torque must be considered when calculating shear stress (Tau). The correct formulas for these calculations are provided, along with external references for further understanding.

PREREQUISITES
  • Understanding of beam mechanics and structural analysis
  • Familiarity with bending stress and shear stress calculations
  • Knowledge of moment of inertia and its significance in beam design
  • Basic grasp of axial loads and torque effects on beams
NEXT STEPS
  • Study the calculation of moment of inertia for various beam cross-sections
  • Learn about the first moment of area (Q) and its application in shear stress calculations
  • Research the polar moment of inertia (J) and its role in torsional analysis
  • Explore advanced topics in structural analysis, including combined loading effects on beams
USEFUL FOR

Structural engineers, civil engineering students, and professionals involved in beam design and analysis will benefit from this discussion, particularly those looking to enhance their understanding of V and M diagrams.

hansthegerman
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I should know how to do this because I know I've learned it a year ago. This is just a refresher homework assignment and for the life of me I can't remember how to do this. In the attachments, I'm including the problem, the questions, as well as my attempts, which are likely, very wrong. Any help would be greatly appreciated.

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Since the beam is built-in on the left end, there should be a non-zero bending moment there. Your moment diagram shows the moment at the left end is zero.
 
So should my M diagram look more like:
photo.jpg


and how do I figure out the moment of inertia without a mass?
 
The bending stress of a beam is inversely proportional to the second moment of area of the cross section of the beam. Although it is usually referred to as the moment of inertia, it is not the same as the mass moment of inertia of a body.
 
So mass has nothing to do with I. Would the I in this case be I=(Pi*r^4)/4? If so my stress is close to the answer. I get 82,760 when the answer is 84,670. What about Tau? Where Tau=V*Q/Ib. Or would I use a different formula to find Tau since this is a Cylinder?
 
The answer you got for stress is only due to bending. If you look closely at the diagram, you will see a separate axial load applied at the right (free) end. This load also produces a contribution to sigma-x.

Similarly, the shearing stress due to the transverse loading of the beam must also be combined with the shearing stress due to the torque applied at the free end of the beam.
 
OH! That makes complete sense. Okay so now for Tau, the two formulas I'm looking at are Tau=(VQ/IT) but now what is Q and I? and for the Torsion portion to add to the first tau, would I do Tau=(TR)/J, so R is radius, t is torque=15,000, what is J?

Thanks a bunch BTW, You're helping out in a huge way.
 
I is the same quantity that was used in calculating the bending stress, the moment of inertia of the cross sectional area of the beam. Q is the first moment of cross sectional area of the beam. Its calculation is described in the following link:
http://www.optics.arizona.edu/optomech/references/OPTI_222/OPTI_222_W10.pdf

J is another section constant, called the polar moment of inertia.

This is a link to another handy reference:

http://www.eng.uah.edu/~wallace/mae466/DOC/bas_str.pdf
 
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