Masters in Physics: Proving Properties of Gamma Matrices

bubblehead
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I've just started a masters in physics after a 4-year break and am having some real trouble getting back into the swing of things! We have been asked to prove some properties of gamma matrices, namely:

1. \gamma^{\mu+}=\gamma^{0}\gamma^{\mu}\gamma^{0}

2. that the matrices have eigenvalues +/- 1, +/- i

3. The trace of \gamma^{\mu} is zero

4. if \gamma_{5} = -i\gamma^{0}\gamma^{1}\gamma^{2}\gamma^{3} then \gamma_{5},\gamma^{\mu}= 0, \gamma^{2}_{5}=I, eigenvalues = +/- 1


For #1 we are to use the Clifford algebra. We have not been given the definitions of the the gamma matrices -- I don't know if we are expected to know these or if they are irrelevant for the proof. We are also given that gamma 0 is equal to its conjugate transpose and gamma i (i = 1,2,3) is equal to its conjugate transpose times -1. I don't even know where to start on this one -- not quite clear on how the multiplication of the matrices works.

#2 I can do if I take each matrix individually, but how do it do it for the 'general' case of \gamma^{\mu}? By \gamma^{\mu} does it mean I need to take all gammas at once as a set/group/4-vector (how can it be a vector if its components are matricies?), or does it mean for a general gamma mu, where mu = 0,1,2,3?

#3 Same as above, fine if I take each matrix individually, but how to do it generally?

# 4 I can do the eigenvalues and the gamma-five-squared = identity, but I'm not sure about the commutator? Again, do I use some 'general' gamma mu?


I have never had to use tensors before so that whole area is still not quite clear to me -- I understand the concept but not really how tensor operations work.
 
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You will need to use the defining property of the gamma matrices, namely:
\gamma^\mu \gamma^\nu + \gamma^\nu \gamma^\mu = 2 \eta^{\mu\nu}
Most of these should follow from this. For example, this tells you that
(\gamma^0)^2 = 1, (\gamma^i)^2 = -1
What can you conclude about the eigenvalues from this?
 
As they are unitary matrices, it means the eigenvalues are +/- i, +/- 1. Hooray!

I am still stuck on how to show 1.

Using the defining property I can generalize, (\gamma^{\mu})^{2}=\eta^{\mu\mu}. I am given the conjugate transposes for 0 and i, putting those together I get

\gamma^{\mu+}=-\eta^{\mu\mu}\gamma^{\mu}

I can substitute (\gamma^{\mu})^{2} for \eta^{\mu\mu}. For -1 I can substitute the square of gamma zero, giving

\gamma^{\mu+}=\gamma^{\mu}\gamma^{\mu}\gamma^{0}\gamma^{0}\gamma^{\mu}

How do I continue from here? I am stuck on how to rearrange this because the matrices are not commutative. I tried substituting a rearranged defining property for \gamma^{0}\gamma^{\mu} but it didn't seem helpful.
 
Use the anticommutation relation to switch the order of \gamma^0 and \gamma^\mu in \gamma^0\gamma^\mu\gamma^0. It doesn't matter which \gamma^0 you use.
 
Not sure how to do that. Everything I try seems to just cancel back out, e.g.

\gamma^{0}\gamma^{\mu}\gamma^{0} = \gamma^{0}(2\eta^{\mu 0}-\gamma^{0}\gamma^{\mu})

=\gamma^{0}2\eta^{\mu 0}-(\gamma^{0})^{2}\gamma^{\mu}

= \gamma^{0}(\gamma^{\mu}\gamma^{0}+\gamma^{0}\gamma^{\mu})+\gamma^{\mu}

=\gamma^{0}\gamma^{\mu}\gamma^{0}+\gamma^{0})^{2}\gamma^{\mu}+\gamma^{\mu}

=\gamma^{0}\gamma^{\mu}\gamma^{0}

How does this help me?
 
What does the second line evaluate to when \mu=0 and when \mu=i?
 
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