How Many 200 mg Tablets Are Needed for a 2% Solution in a 3 oz Bottle?

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To create a 2% solution using 200 mg tablets in a 3-ounce bottle of water, first convert the volume of water to grams, noting that 3 ounces is approximately 88.5 ml, which equals 88.5 grams. A 2% solution requires 2 grams of solute per 100 grams of solution, meaning you need 1.77 grams of the active ingredient for 88.5 grams of water. Since each tablet is 0.2 grams, you would need about 8.85 tablets to achieve the desired concentration. Therefore, adding approximately 9 tablets to the 3-ounce bottle will create a 2% solution.
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Hello, I need your help on a calculation...

I have 200 milligram dissolvable tablets, and a 3 ounce dropper bottle of water. How many tablets would I need to add to the water to make a 2% solution?

The chemistry/math is a bit confusing to me because the tables are measured in mass (i.e. mg), whereas water is measured in volume (i.e. oz.).

Thanks in advance for your help

-Rich
 
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It would help if you had everything in the same systems of units...leave your tablets in milligrams but convert your bottle of water from ounces into grams (or milligrams)...things should then get easier
 
I'm terrible at math.

Does anyone know the answer?

Thanks.
 
one liter of water contains 1000 grams = 1000 ml
one 200 milligram tablet = .2 grams
so 100 tablets = 20 grams
20g/1000g = 2% solution

3 oz = 88.5 ml
so x / 88.5 = 100 / 1000
so you add 8.85 ( 200 mg ) tablets / 3 oz water = 2% solution
 
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