Find Math Help: Solving for Jet Speed and Heat Transfer Equation

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The discussion revolves around two math problems: calculating jet speed and deriving a heat transfer equation. For the jet speed problem, the formula used is distance equals rate times time, leading to the conclusion that the jet travels at 550 miles per hour relative to the air. In the heat transfer equation, the user correctly expresses T2 as T2 = (Ht / A) + T1, confirming their understanding of the relationship between heat, area, and temperature difference. Participants affirm the solutions provided, reinforcing the accuracy of the calculations. Overall, the thread emphasizes problem-solving in physics and mathematics.
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1) A jet took 6h to fly against headwinds of 50 miles/hour from city A to B. It took 5H on the return trip when the winds became tailwinds of 50miles/hour. How fast does the jet travel relative to the air?


2) The amount of heat H which passes through wall "t" thick is proportional to the product of the area "A" of a wall T2 - T1, the differnce in temperature of the surfaces of the wall and is inversly proportional to "t". Express the equation and solve for T2.


For #2 I got to: T2 = ((HT) / A) + T1

Is that right? thanks.

Thanks a lot guys, been havinga lot of trouble with these.
 
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#1.
A distance one way is the same as on a way back (AB = BA).
[distance] = [rate]*[time]
(x-50)6 = (x+50)5
x=550.

#2.
You got it right! Why doubt?
Just use "t" instead of "T":
T2 = Ht / A + T1
 
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