Math *Questions* Involving Probablity

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To achieve at least a 50% chance of rolling two sixes with two six-sided dice, one must roll the dice approximately 25 times. In the second question regarding diabetes testing, the conditional probability that a person has diabetes given a positive test result is about 55%. This calculation involves applying Bayes' theorem, considering the test's accuracy rates and the prevalence of diabetes in the population. The initial estimates provided were close, with one participant arriving at approximately 5.78% and another at 5.89%. Overall, the discussion emphasizes the importance of understanding probability concepts and their applications in real-world scenarios.
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Homework Statement



1) How many times must you roll two six-sided dice for there to be at least a 50% chance that you roll two 6's at least once?2) It is estimated that 5.9% of Americans have diabetes. Suppose a medical lab uses a test for diabetes that 98% accurate for people who have the disease and 95% accurate for the people who do not have it. Find the conditional probability that a randomly selected person actually has diabetes given that the lab test says they have it.

Homework Equations



-None-

The Attempt at a Solution



Question One:

Work: chance of rolling a six(dice one) x chance of rolling a six(dice two) x one half

1/6 x 1/6 x 1/2 = 1/72

72 rolls?

Question Two:

Work:

P(accurate) x (accurate|don't have diabetes) - P(accurate) x (accurate|have diabetes)
(.95 x .941)-(.98 x .059)= .89395-.83163 = about 5.782% ?
 
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q1: mathematicians look at this problem in reverse and instead ask what's the probability of not getting two sixes in a row and then multiply it over and over until they get to the 50% mark and the number of times they multiplied will be the number of rolls needed.

q2: is a a bayesian conditional probability question, you need the bayes eqn to compute it:

p(A given B) = p(B given A) * p(A) / p(B) or succinctly p(A|B)=p(B|A)p(A)/p(B)

where A= prob of having diabetes and B=prob of positive test
 
My approach to problem two was to set an arbitrary number of people in the population (say 1 million) and then figure out the number of people who A) have the disease and get a positive test result and then B) don't have the disease, but still get a positive result.
Then the answer is A/(A+B), which was ~55%I only approached the problem this way because I'm not familiar with bayesian equation that jedishrufu mentioned.
 
Your answer of 5.78% is close to mine of 5.89%
 
darshanpatel said:

Homework Statement



1) How many times must you roll two six-sided dice for there to be at least a 50% chance that you roll two 6's at least once?


2) It is estimated that 5.9% of Americans have diabetes. Suppose a medical lab uses a test for diabetes that 98% accurate for people who have the disease and 95% accurate for the people who do not have it. Find the conditional probability that a randomly selected person actually has diabetes given that the lab test says they have it.


Homework Equations



-None-

The Attempt at a Solution



Question One:

Work: chance of rolling a six(dice one) x chance of rolling a six(dice two) x one half

1/6 x 1/6 x 1/2 = 1/72

72 rolls?

Question Two:

Work:

P(accurate) x (accurate|don't have diabetes) - P(accurate) x (accurate|have diabetes)
(.95 x .941)-(.98 x .059)= .89395-.83163 = about 5.782% ?


Answer for 1 is n = 25. Answer for 2 is 5782/10487 ≈ 0.55, or about 55%.

RGV
 
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