I'm stuck on this problem that involves drawing a phase portrait but I'm at a stand still. Find the general solution to the following differential equation: [1 -12 -14] x'= [1 2 -3]*x [1 1 -2] the eigeinvalues that I found are 1 , +5i, -5i the general solution that I found is c1e^e + c2[cos5t+5sin5t] + c2[-5cos5t+sin5t] + c3 + c3t[1-5i] [-7] [cos5t ] [sin5t ]  [1 ] [6 ] [cos5t ] [sin5t ]  [1 ] Am I suppose to have imaginary values in my solution? I'm supposed to find the solution if x(0)=2i-5j+3k I just plug 0 in for all the t's and solve for the constants which is no problem for me. The problem that I'm having is the fact that I have an imaginary value in the solution. I'm also suppose to find the phase portrait.