MHB Matrix Addition: OK - No Examples Found

  • Thread starter Thread starter karush
  • Start date Start date
  • Tags Tags
    Addition Matrix
Click For Summary
The discussion revolves around the lack of examples for matrix addition in a specific textbook, prompting questions about vector space definitions. Participants emphasize the importance of understanding the conditions that define a vector space, such as the existence of a zero vector and the existence of negative vectors. The conversation includes a mathematical exploration of solving equations related to these vector space conditions. A specific example is provided to illustrate how to derive values for the variables involved. Overall, the thread highlights the need for clarity and examples in understanding matrix addition and vector spaces.
karush
Gold Member
MHB
Messages
3,240
Reaction score
5
View attachment 8764

OK from the text bk I did not see any example of this
the circle red is mine ... why is this here

so not sure how these questions are to be answered.

Much Mahalo
 

Attachments

  • mhb.s2.9.1.png
    mhb.s2.9.1.png
    4.7 KB · Views: 139
Physics news on Phys.org
karush said:
I did not see any example of this
Which textbook are you using? Are you sure it does not contain solved similar examples?

karush said:
the circle red is mine ... why is this here
By definition. The author (or anybody) has the right to define whatever concepts they like.

karush said:
so not sure how these questions are to be answered.
The problem asks whether this is a vector space. Do you know the definition of a vector space?
 
One condition is that a vector space have a 0 vector. That means that there exist a vector 0 such that v+ 0= v for every vector v. Here it is clear that \begin{bmatrix}0 \\ 0 \end{bmatrix} is that 0 vector.

Another condition is that every vector has a "negative". That is, given a vector v, there exist a vector u such that u+ v= v+ u= 0.

Here that means that, given v= \begin{bmatrix}x_1 \\ x_2 \end{bmatrix}, there exist a vector u= \begin{bmatrix}x_2 \\ y_2 \end{bmatrix} such that u+ v= \begin{bmatrix}x_1+ x_2+ x_1x_2 \\ y_1+ y_2+ y_1y_2\end{bmatrix}= \begin{bmatrix}0 \\ 0 \end{bmatrix}

So the question is, given numbers x_1, y_2, can we solve the equations x_1+ x_2+ x_1x_2= 0 and y_1+ y_2+ y_1y_2= 0 for x_1 and x_2? We can write the first equation x_1= -(x_2+ x_1_2)= -x_2(1+ x_1) and then x_2= -\frac{x_1}{1+ x_1}. What if x_1= -1?
 
Last edited:
Thread 'How to define a vector field?'
Hello! In one book I saw that function ##V## of 3 variables ##V_x, V_y, V_z## (vector field in 3D) can be decomposed in a Taylor series without higher-order terms (partial derivative of second power and higher) at point ##(0,0,0)## such way: I think so: higher-order terms can be neglected because partial derivative of second power and higher are equal to 0. Is this true? And how to define vector field correctly for this case? (In the book I found nothing and my attempt was wrong...

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K