Matrix Determinants: Find x for Invertibility

AI Thread Summary
A matrix is invertible when its determinant is non-zero, and the discussion revolves around finding the values of x that satisfy this condition. The user encountered confusion regarding the factoring of (1 - x) from a minor matrix, questioning whether it should be factored out from both rows. Clarification was provided that only one instance of (1 - x) can be factored out, as it is common to all members of the matrix. The conversation also referenced the impact of scalar multiplication on the determinant, confirming that scaling a row by a factor m scales the determinant by the same factor. Understanding these concepts is crucial for determining the invertibility of the matrix.
SherlockOhms
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Homework Statement


For which values of x is the matrix (see attachment) invertible?


Homework Equations


Row ops. Cofactors etc..


The Attempt at a Solution


Well, a matrix is only invertible when it's determinant is non zero. I've begun doing some row ops and have just hit a little snag. If you look at the attachment you'll see that I can facto (1 - x) out from the minor matrix. I remember hearing in a lecture that you have to factor out (1 - x) from both the top and bottom row of the matrix (i.e. you'll have (1 -x)^2 factored out instead of just (1 - x). Could somebody explain why you don't just factor out (1 - x) one like you would with factoring a scalar out of a matrix as normal?x
 
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In the reduced 2x2 matrix, the factor (1-x) is common to all of the members of the matrix. You can only factor it out once. Whatever you heard about factoring the matrix was incorrect.

See this article: http://en.wikipedia.org/wiki/Matrix_(mathematics)

specific topic: scalar multiplication ofa matrix
 
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Thanks for clearing that up.
 
Even with a scalar, wikipedia confirms that to scale a row by m scales the determinant by m, which is clear if you think of the formula for the determinant.
 
Yeah. That's actually what got me thinking about it in the first place.
 
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