- #1
patchwerk
- 3
- 0
Hey guys, need some quick help before an exam
I have a differential eqn.
x' = | 0 1 | *x , and initial conditions x(0) = |2|
| -25 10 | |3|
I find that there are two eigenvalues 5, and 5
The corresponding eigenvector to 5 is [1 5] (vertical)
So i need to find a generalized eigenvector,
I do so in the form
(A - 5lambda)v_2 = v_1
I then find that v_2 = [0 1 ] (vertically)
I don't know what form my solution should now be in
Please help, I have an exam at 7,
Thanks,
Evan
I have a differential eqn.
x' = | 0 1 | *x , and initial conditions x(0) = |2|
| -25 10 | |3|
I find that there are two eigenvalues 5, and 5
The corresponding eigenvector to 5 is [1 5] (vertical)
So i need to find a generalized eigenvector,
I do so in the form
(A - 5lambda)v_2 = v_1
I then find that v_2 = [0 1 ] (vertically)
I don't know what form my solution should now be in
Please help, I have an exam at 7,
Thanks,
Evan