What is the Determinant of an Idempotent Matrix?

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An idempotent matrix P satisfies the condition P^2 = P, leading to the conclusion that det(P) must equal 0 if P is not the identity matrix. The determinant relationship det(P^2) = det(P) implies det(P)^2 = det(P), which can be factored to show that det(P) must be either 0 or 1. However, since P is specified to be different from the identity matrix, det(P cannot be 1, confirming that det(P) must be 0. The discussion also touches on the idempotency of a specific matrix form, prompting users to verify this by calculating A^2.
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A matrix P is called idempotent if P^2 = P. If P is idempotent and P =/= I show that det(P)=0.

I don't really know where to go with this but i have a feeling that it involves taking the det of each side.

det(P^2) = det(P)
det(P)det(P) = det(P)

where to from here if that's even the right step/method to take, or if its even right at all >_>

Thanks :)
 
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looks fine to me; now for what values of det(P) does that equation hold?
 
det(P) = 1 or 0
 
Okay, if detP=1, and P^2=P, what matrix must P be?
 
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Hint: use the fact that if det(P) \neq 0, then P is invertible. Multiply P^2=P by P^{-1}.
 
but it says det(P)=/=1. How do you show that det(P)=0?
 
det(P2) = det(P)

=> det(P)^2-det(P)=0

This is the same as t^2-t=0 where t=det(P). Factorise and use that fact that P=/= I
 
I have a questions:
if A=I-X(X'X)^-1X'
is it A idempotent?
 
kendarto: don't jump into another poster's thread.

try to calculate A^2 and answer this for yourself.
 
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