Max Force Applied to Sled Before Slipping: 70N

AI Thread Summary
To determine the maximum force applied to the sled before the block slips, first calculate the frictional force between the block and the sled, which is 49N (70N * 0.700). Next, assess the frictional force between the sled and the ground, which is 6N (60N * 0.100). The maximum force that can be applied to the sled without causing the block to slip is the sum of the frictional forces, resulting in a total of 55N (49N + 6N). Thus, the maximum force before slipping occurs is 55N. Understanding these frictional interactions is crucial for solving similar physics problems.
stevengates45
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Im lost on this one & any help whatsoever would be more than appreciated... Here is the problem...

You have a block that weighs 70N that rests on a sled that weighs 60N. The coefficient of friction between the box & the sled is .700 & the coefficient of friction between the sled & the ground is .100. So what can the max force applied be before the top box slips?
 
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Consider the sum of the forces acting on the combined system (sled and block) and then the sum of the forces acting on the block.
 
Thanks... Appreciate it...
 

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