Max # of 60W Light Bulbs in a 30A 220V Circuit

AI Thread Summary
A 220V circuit fused for 30 amps can safely support a maximum of 30 amps multiplied by 220 volts, equating to 6600 watts. Each 60-watt incandescent bulb draws 60 watts, so dividing 6600 watts by 60 watts per bulb indicates that up to 110 bulbs can be used simultaneously without tripping the fuse. However, practical considerations such as inrush current and wiring limits may reduce this number. The discussion emphasizes the importance of understanding power calculations, specifically using the formula P = IV for determining safe load limits. Proper calculations and considerations are crucial for safe electrical circuit usage.
tDexx
Messages
6
Reaction score
0

Homework Statement


A 220 volt circuit is fused for 30 amps. How many 60 watt incandescent soft whote light bulbs with tungsten filament burning at 3,0000 celsius can be used at the same time in the circuit without tripping the fuse?


Homework Equations


N/A

The Attempt at a Solution


(w/220)=30
220=30 amps(w)
220/30 amps=7.33 watts
 
Physics news on Phys.org
tDexx said:

Homework Statement


A 220 volt circuit is fused for 30 amps. How many 60 watt incandescent soft whote light bulbs with tungsten filament burning at 3,0000 celsius can be used at the same time in the circuit without tripping the fuse?


Homework Equations


N/A

The Attempt at a Solution


(w/220)=30
220=30 amps(w)
220/30 amps=7.33 watts

At least have a look at this:

http://en.wikipedia.org/wiki/Power_(physics)

Go to the electric power section for some useful formulae. Those same formulae will be in your textbook.
 
Unfortunately i don't have a textbook to go with my homework...
 
tDexx said:

Homework Statement


A 220 volt circuit is fused for 30 amps. How many 60 watt incandescent soft whote light bulbs with tungsten filament burning at 3,0000 celsius can be used at the same time in the circuit without tripping the fuse?


Homework Equations


N/A
In one of your other posts you listed P = IV. That would be really useful here.

The Attempt at a Solution


(w/220)=30
220=30 amps(w)
220/30 amps=7.33 watts

See above.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top