Max Speed of Mass on Spring: Calculate Vmax with 2πfA

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The maximum speed (Vmax) of a mass on a spring can be calculated using the formula Vmax = 2πfA, where f is the frequency and A is the amplitude. To derive this without calculus, one can apply the conservation of energy principle by equating maximum potential energy to maximum kinetic energy. The general equation of motion for a spring is based on simple harmonic motion, which involves sine or cosine functions. Hooke's Law, F = -kx, is also relevant in understanding the relationship between force, spring constant, and displacement. Understanding these concepts allows for the calculation of Vmax effectively.
Mary1910
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Prove that the maximum speed (Vmax) of a mass on a spring is given by 2πfA.

I have no idea how to solve this problem. I have not taken calculus yet, and I am really confused on how to come up with a solution for this. Any help would be appreciated. Thanks
 
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With conservation of energy, you can solve it without Calculus. Compute max potential energy. Set equal to max kinetic energy. Solve for v.
 
As Dr. Courtney says, but first you need to quote the general equation for the motion.
 
Ok I'm still lost. Should I be using, E=½mv^2 + ½kx^2 for the general equation for the motion?
 
Mary1910 said:
Ok I'm still lost. Should I be using, E=½mv^2 + ½kx^2 for the general equation for the motion?
No, that's just conservation of energy in a spring. What's the equation of simple harmonic motion? Or, you can use the above equation if you know the relationship between f, k and m for a spring.
 
haruspex said:
What's the equation of simple harmonic motion?

Hooke's Law: F=-kx
 
The general equation of motion should have a sine or cosine in it.
 
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