Maxima in a diffraction grating

AI Thread Summary
A diffraction grating with slits of width 300 nm and separation 900 nm is illuminated by monochromatic light of wavelength 600 nm. The equation mλ = dsinθ is used to determine the maxima in the diffraction pattern. The user initially calculated m as 1.5 but later realized the need to use the modified equation (a+b)sinθ = mλ, which includes both the slit width and separation. This adjustment is necessary because the distance between the centers of adjacent slits is the sum of the slit width and the separation. Understanding this concept clarifies how to accurately calculate the number of maxima in the pattern.
L_landau
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Homework Statement


A diffraction grating is made up of slits of width 300 nm with separation 900 nm. The grating is illuminated by monochromatic plane waves of wavelength l 600 nm at normal incidence. How many maxima are there in the full diffraction pattern?

Homework Equations


mλ = dsinθ

The Attempt at a Solution


I thought that I could just use the above equation and doing so I get m = 1.5. However, the solution uses
(a+b)sinθ = mλ . Can I really just add the slit width and the separation width like that?
 

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You need the distance between the centers of adjacent slits, if 900 nm is the space between their edges you have to add the slit width.
 
Oh that makes sense! Thank you!
 
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