Maximizing Speed in Simple Harmonic Motion | SHM Homework Solution

AI Thread Summary
To double the maximum speed of simple harmonic motion (SHM), one can increase the amplitude (A) by a factor of two while keeping the spring constant (k) and mass (m) constant. The maximum speed is calculated using the formula v_max = sqrt{k/m}A. Since maximum speed occurs at the equilibrium point, doubling the amplitude directly results in doubling the maximum speed. This approach effectively demonstrates the relationship between amplitude and speed in SHM.
recklessid
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Homework Statement



How could you double the maximum speed of a SHO?

Homework Equations



v_max = sqrt{k/m}A

The Attempt at a Solution



The speed is at its maximum when it's period is complete and is passing through its equilibrium point. k and m can be kept at the same. BUt if we double the value of A, then v_max should also be doubled as well.

Is this right?
 
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You are correct--double the amplitude and you double the max speed.
 
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