Maximizing Wind Power: Calculating Capacitance for Energy Storage

AI Thread Summary
To store energy from a wind power plant during low wind periods, a parallel plate capacitor is proposed, with a desired output of 20 MW for three days at a voltage of 50,000 V. The capacitance formula C = k * (ε₀A/d) is essential for calculating the required area, where k is the dielectric constant, ε₀ is the permittivity of free space, A is the area, and d is the separation distance. The discussion highlights the need to first calculate the total energy output over three days to determine the necessary capacitance. Participants express confusion about relating area to capacitance and seek clarification on the calculations involved. The conversation emphasizes understanding the energy storage requirements and the physical dimensions of the capacitor.
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Homework Statement



A wind power plant will not produce as much energy when the wind slows down. In order to provide power during these time periods it is proposed to store some power when it is operating in high winds in a capacitor. If it is desired to store the energy to power a town at 20 MW (20*10^6) for three days, what is the area of a parallel plate capacitor (seperation, d, 3 meters) filled with air if the voltage is 50,000 V? Is there a way to reduce this size? Explain.

Homework Equations



K = 1.0006

The Attempt at a Solution



I cannot figure out where to start. I need to relate area to the capacitor, but I don't know if a Capacitor has an area l*w and then there is just a distance d seperating them or what. I'm lost and tired. Can someone help?
 
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Start with the equation that gives the capacitance of a parallel plate, air-filled capacitor. What is that equation?
 
C=k\cdot\frac{\epsilon_0A}{d}?
 
Thanks for the disappearing act; I was about to go to sleep.
 
Correct capacitance expression. When you wake up, figure out how much energy the power plant produces in three days. All that energy is to be stored in the capacitor.
 
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