(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The circumference of a sphere was measured to be 73.000 cm with a possible error of 0.50000 cm. Use linear approximation to estimate the maximum error in the calculated surface area

2. Relevant equations

[tex]SA=4\pi\(r^2[/tex] Eq1.

[tex]dV=8\pi\(rdr[/tex] Eq2.

[tex]c=2\pi\(r[/tex] Eq3.

3. The attempt at a solution

I solved for the radius by [tex]r=\frac{73}{2\pi}[/tex]

I then plugged r into Eq2, I set [tex]dr= \frac{.5}{2\pi}[/tex]

I get something like 134.98 and it is wrong.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Maximum eror in calculated surface area

**Physics Forums | Science Articles, Homework Help, Discussion**