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## Homework Statement

The circumference of a sphere was measured to be 73.000 cm with a possible error of 0.50000 cm. Use linear approximation to estimate the maximum error in the calculated surface area

## Homework Equations

[tex]SA=4\pi\(r^2[/tex] Eq1.

[tex]dV=8\pi\(rdr[/tex] Eq2.

[tex]c=2\pi\(r[/tex] Eq3.

## The Attempt at a Solution

I solved for the radius by [tex]r=\frac{73}{2\pi}[/tex]

I then plugged r into Eq2, I set [tex]dr= \frac{.5}{2\pi}[/tex]

I get something like 134.98 and it is wrong.

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