# Maximum eror in calculated surface area

1. Mar 9, 2007

### Weave

1. The problem statement, all variables and given/known data
The circumference of a sphere was measured to be 73.000 cm with a possible error of 0.50000 cm. Use linear approximation to estimate the maximum error in the calculated surface area

2. Relevant equations
$$SA=4\pi\(r^2$$ Eq1.
$$dV=8\pi\(rdr$$ Eq2.
$$c=2\pi\(r$$ Eq3.

3. The attempt at a solution
I solved for the radius by $$r=\frac{73}{2\pi}$$
I then plugged r into Eq2, I set $$dr= \frac{.5}{2\pi}$$
I get something like 134.98 and it is wrong.

Last edited: Mar 9, 2007
2. Mar 9, 2007

### Weave

Never mind, I figured it out.

3. Mar 9, 2007

### Dick

You are calculating the error in the measured volume - not in the measured surface area.

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