- #1

Entropia5

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## Homework Statement

A ball is launched at an angle of 28 degrees off a platform. The initial velocity is 53m/s. When dropped straight down, the ball hits the ground after 1.6 seconds.

What is the maximum height of the ball?

## Homework Equations

Xf = Xi + Vi(t) + (1/2)(a)(t^2)

Vix = (Vi)(cos@)

## The Attempt at a Solution

I was able to figure out the height of the platform from which the ball was launched, using the the 1.6s times gravity, to get 12.5m high.

I figured out that the ball traveled 5.54 seconds by solving for t in the equation Yf = Yi + Viy(t) + (1/2)(g)(t^2) and Viy=(Vi)(sin@). Using this, I found that the ball landed 259.25m away.

I was thinking I could use the equation of the y/x-graph to find the two X-values when Y = 0, and find Y at the middle X point, to get the highest point of the ball.

Which equation exactly represents this y/x-graph line? Any other suggestions would be highly appreciated!