1. The problem statement, all variables and given/known data A ball is launched at an angle of 28 degrees off a platform. The initial velocity is 53m/s. When dropped straight down, the ball hits the ground after 1.6 seconds. What is the maximum height of the ball? 2. Relevant equations Xf = Xi + Vi(t) + (1/2)(a)(t^2) Vix = (Vi)(cos@) 3. The attempt at a solution I was able to figure out the height of the platform from which the ball was launched, using the the 1.6s times gravity, to get 12.5m high. I figured out that the ball traveled 5.54 seconds by solving for t in the equation Yf = Yi + Viy(t) + (1/2)(g)(t^2) and Viy=(Vi)(sin@). Using this, I found that the ball landed 259.25m away. I was thinking I could use the equation of the y/x-graph to find the two X-values when Y = 0, and find Y at the middle X point, to get the highest point of the ball. Which equation exactly represents this y/x-graph line? Any other suggestions would be highly appreciated!