Maximum Height of model rocket

DerekF
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Homework Statement


A model rocket is launched with an initial velocity of 55 m/s. Its height as a function of time can be modeled by h(t) = -4.9t2 + 55t. Determine the maximum height reached by the rocket.

Homework Equations


h(t) = -4.9t2 + 55t

The Attempt at a Solution



h'(0) = 55, since h'(t) = -4.9(0) + 55 = 55 <-- Height reached within time interval 0 - 1 s

I am not sure how to approach this problem though I assume it has something to do with the initial velocity since it is included in the question. The quadratic formula was used in another problem but it isn't applicable here as far as I can tell. It sounds like I need to find the maximum time or t, in order to be able to find the maximum height. If this isn't possible, would the correct thing be to substitute arbitrary values for time until the height is no longer increasing or positive? If not, I have absolutely no idea.

Any help would be great. Thank you.* Edit *

Following the logic above it seems like the maximum height would be approximately 153.6 metres after 6 seconds. If this is correct, is there a proper way to express this or find a more precise value for t?
 
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DerekF said:

Homework Statement


A model rocket is launched with an initial velocity of 55 m/s. Its height as a function of time can be modeled by h(t) = -4.9t2 + 55t. Determine the maximum height reached by the rocket.


Homework Equations


h(t) = -4.9t2 + 55t


The Attempt at a Solution



h'(0) = 55, since h'(t) = -4.9(0) + 55 = 55 <-- Height reached within time interval 0 - 1 s

I am not sure how to approach this problem though I assume it has something to do with the initial velocity since it is included in the question. The quadratic formula was used in another problem but it isn't applicable here as far as I can tell. It sounds like I need to find the maximum time or t, in order to be able to find the maximum height. If this isn't possible, would the correct thing be to substitute arbitrary values for time until the height is no longer increasing or positive? If not, I have absolutely no idea.

Any help would be great. Thank you.


* Edit *

Following the logic above it seems like the maximum height would be approximately 153.6 metres after 6 seconds. If this is correct, is there a proper way to express this or find a more precise value for t?

Step 1: plot a graph of the function h(t), to see what is happening.
Step 2: translate the insights from your graph into a formal statement.
 
DerekF said:

Homework Equations


h(t) = -4.9t2 + 55t

The Attempt at a Solution



h'(0) = 55, since h'(t) = -4.9(0) + 55 = 55 <-- Height reached within time interval 0 - 1 s

The correct expression for the derivative of the height function is:

h'(t) = -9.8t + 55
 
SteamKing said:
The correct expression for the derivative of the height function is:

h'(t) = -9.8t + 55

Yeah, oops. I had that written down on paper but messed up here.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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