Maximum kinetic friction-combined with a projectile problem

AI Thread Summary
A cannon is tasked with launching emergency packets to a roof 125 meters high and 50 meters away, requiring calculations for the initial speed and launch angle to ensure the packets land gently. The discussion highlights a misunderstanding of horizontal versus vertical velocity, leading to an incorrect calculation of the coefficient of kinetic friction. The correct horizontal velocity was determined to be 9.9 m/s, resulting in an acceleration of 1.6335 m/s². The final calculated coefficient of kinetic friction is approximately 0.1667, with a reminder to round results to reasonable precision. The conversation emphasizes the importance of clarity in physics problems involving projectile motion and friction.
Poetria
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Homework Statement


A cannon at ground level is shooting emergency packets to people stranded on the roof of a flooded building of height H=125 meters. The corner of the building is located a distance D=50 meters from the cannon. It is desired that the incoming packets are flying tangent to the roof as shown so that they land gently with as little impact as possible and slide along to a stop.

Find the initial speed v0 and at what angle θ (in degrees) the cannon should be aimed to achieve the above scenario
If the roof has length L=30 meters (not shown) what is the minimum coefficient of kinetic friction between the food packets and the roof such that the packets do not slide off the other side?

Homework Equations



v^2(x)=v^2_i,x+2a*x(x−xi)

The Attempt at a Solution



I only have a problem with the third part but I think I have found my mistake. I have confused horizontal velocity with vertical velocity. I got a very strange value for mu, much too high.

When packets land on a roof, there is no vertical velocity involved and I have already computed the value for the horizontal: v=9.9.


0=9.9^2-2*a*30
a=1.6335

m*a=mu*m*g
a=mu*g
mu=1.6335/9.8
mu=0.1666836734693877551020408163265306122448979591836734


 
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Looks correct.
Poetria said:
mu=0.1666836734693877551020408163265306122448979591836734
Are you sure it is not 0.1666836734693877551020408163265306122448979591836733[/color]? You should round final results to reasonable precision.
 
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Right. Many thanks. :)
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