Maximum Likelihood Estimator for Exponential Density Function

twoski
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Homework Statement



Given f(x;λ) = cx^{2}e^{-λx} for x ≥ 0

Determine what c must be (as a function of λ) then determine the maximum likelihood estimator of λ.

The Attempt at a Solution



So I'm supposed to integrate this from 0 to infinity, from what i can gather.

Let u = x^{2}, du = 2xdx, dv = e^{-λx} and v = -e^{-λx} / λ

After a bit of work i end up with:

-c/λ [ x^{2}e^{-λx}|_{0}^{∞} + 2( xe^{-λx}/λ |^{∞}_{0}) ]

What throws me off is that evaluating this leaves me with -c/λ( 0 ), which has to be wrong...
 
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twoski said:

Homework Statement



Given f(x;λ) = cx^{2}e^{-λx} for x ≥ 0

Determine what c must be (as a function of λ) then determine the maximum likelihood estimator of λ.

The Attempt at a Solution



So I'm supposed to integrate this from 0 to infinity, from what i can gather.

Let u = x^{2}, du = 2xdx, dv = e^{-λx} and v = -e^{-λx} / λ

After a bit of work i end up with:

-c/λ [ x^{2}e^{-λx}|_{0}^{∞} + 2( xe^{-λx}/λ |^{∞}_{0}) ]

What throws me off is that evaluating this leaves me with -c/λ( 0 ), which has to be wrong...

You have to integrate the second term from 0 to infinity, not just evaluate it. You'll need to integrate by parts again.
 
twoski said:

Homework Statement



Given f(x;λ) = cx^{2}e^{-λx} for x ≥ 0

Determine what c must be (as a function of λ) then determine the maximum likelihood estimator of λ.

The Attempt at a Solution



So I'm supposed to integrate this from 0 to infinity, from what i can gather.

Let u = x^{2}, du = 2xdx, dv = e^{-λx} and v = -e^{-λx} / λ

After a bit of work i end up with:

-c/λ [ x^{2}e^{-λx}|_{0}^{∞} + 2( xe^{-λx}/λ |^{∞}_{0}) ]

What throws me off is that evaluating this leaves me with -c/λ( 0 ), which has to be wrong...

It might be easier to recognize that
x e^{-\lambda x} = - \frac{\partial}{\partial \lambda} e^{- \lambda x},
and so forth.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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