- #1
AlbertEinstein
- 113
- 1
The question is find the maximum value of the following function
f(x) = 3cos(4*pi*x-1.3) + 5cos(2*pi*x+0.5).
f(x) = 3cos(4*pi*x-1.3) + 5cos(2*pi*x+0.5).
The maximum value of f(x) is 8.3.
To find the maximum value of f(x), you can take the derivative of the function and set it equal to 0, then solve for x. Plug the value of x into the original function to find the maximum value.
The period of the function f(x) is 0.5, which is the smallest common multiple of the periods of the two cosine functions (2π and 4π).
The maximum value of f(x) occurs at x=0.1 and x=0.6.
Changing the coefficients of the cosine functions will affect the amplitude and phase shift of the function, but it will not change the maximum value. The maximum value will always be 8.3.