Maxium Allowable Current to (+/-) 2% ?

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The discussion revolves around calculating the maximum allowable current in an electric cable to maintain accuracy within 2% for an experiment on the Earth's magnetic field, positioned 7.00 meters away. The relevant equation used is B = [I*μ]/[2*Pi*d]. A participant suggests using the value of 1750 multiplied by 2.0% to determine the current. The calculation yields a maximum allowable current of 35 A. The conversation highlights the importance of precise measurements in electromagnetic experiments.
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Maxium Allowable Current to (+/-) 2% ?

Homework Statement



An experiment on the Earth's magnetic field is being carried out 7.00 from an electric cable.
What is the maximum allowable current in the cable if the experiment is to be accurate to 2.0 ? Assume that Earth’s magnetic field is .


Homework Equations



B = [I*μ]/[2*Pi*d]

The Attempt at a Solution



Check the picture to see how far I've gotten, but it's still wrong. I'm not sure how to attempt this problem.
 

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So any suggestions mates?

Melqarthos
 


you have to use 1750 * 2.0%

1750 * 0.02 = 35 A
 

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