Maxwell-Boltzmann speed distribution derivatives

AI Thread Summary
Molecules enter a vacuum chamber from an oven at constant temperature and pass through a slit before reaching two rotating discs and a detector. The discussion centers on deriving the condition for a molecule to successfully reach the detector, specifically showing that the speed u must equal ωL/θ. The time taken for the particle to travel between the discs must match the time taken for the second disc to reach the correct position, leading to the equation L/u = θ/ω. The conclusion confirms that the most probable speed can be equated to this derived speed condition. This analysis simplifies the problem to a dynamics scenario rather than a complex velocity distribution issue.
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Hi everyone,

Molecules move into a vacuum chamber from an oven at constant T. The molecules then pass through a slit. They reach two rotating discs before finally reaching a detector.

Show that a molecule that passes through the first slit will reach the detector if it has speed, u = ωL/θ.

After it passes through the slit, the beam of particles is directed towards 2 discs that are a fixed distance apart (L). They both have a notch in them, the 2nd disc's notch is offset from the 1st by 1/6∏. T is constant, common angular speed is ω & L = 0.262m.

My question is, do I simply say that the most probable speed is equal to u?

√(2KT/m) = u = ωL/θ

Any clues would be appreciated.

Thanks:)
 
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I think you are looking too deep into the question. It's not about velocity distribution but they have given you a 'scenario' for a fairly straightforward dynamics problem. They just want to find which speed will get "a" molecule through the shutter which the two spinning slits present.
 
You're absolutely right, I completely over-thought the problem. So,

t1 = Time particle takes between the 2 discs = d/u = L/u

t2 = Time taken for disc 2 to reach correct position = θ/ω

For a particle to pass through both notches & hit detector, t1 must equal t2

So,

L/u = θ/ω → Lω/u = θ → u = Lω/θ

Thanks
 
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