Average Speed for Maxwell's Distribution of Molecular Speed

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SUMMARY

The discussion focuses on calculating the average speed of molecules using the Maxwell-Boltzmann distribution, specifically referencing the integration by parts method as outlined in Giancoli's 4th edition, page 481. The integration involves the equation ∫_0^{∞}v^3e^{-av^2}dv, which simplifies to 1/(2a^2) resulting in 2k^2T^2/m^2. The integration by parts technique is crucial for solving this integral, where u = x^2 and dv = x e^{-x^2}dx are identified for the process.

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  • Understanding of the Maxwell-Boltzmann distribution
  • Familiarity with integration techniques, specifically integration by parts
  • Knowledge of thermodynamic concepts such as temperature (T) and Boltzmann's constant (k)
  • Basic calculus skills, particularly with improper integrals
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  • Study the derivation of the Maxwell-Boltzmann distribution in statistical mechanics
  • Practice integration by parts with various functions to strengthen calculus skills
  • Explore applications of the Maxwell-Boltzmann equation in real-world scenarios
  • Learn about the implications of molecular speed distributions in kinetic theory
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RaulTheUCSCSlug
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Using the Maxwell-Boltzmann equation above, there is an example in my book (Giancoli 4th edition p. 481) where they use this to find the average velocity. I understand that it would just be the sum of all the speeds of the molecules divided by the number of molecules. But then I'm having trouble on how they did the integration by parts? Could someone walk me through the process?

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Let a=\frac{m}{2kT}
\int_0^{\infty}v^3e^{-av^2}dv=\frac{1}{a}\int_0^{\infty}ve^{-av^2}dv=\frac{1}{2a^2}=\frac{2k^2T^2}{m^2}

The first equality is integration by parts.
 
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Do you know how to do integration by parts? \int u dv = uv - \int v du . Try u = x^2; dv = x e^{-x^2}dx
 

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