McLaurin Expansion of finite sum

phanhoc
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Would you please find the McLaurin expansion of the following series to help me:
M
Ʃ Binomial(m + q - 1,q) [(a x)^q /((a x + b)^(m + q)]
q=0

where M , m ℂ N^+; a, b > 0;
MANY THANKS FOR YOUR HELP.
 
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By brute force: (ax+b)m+q can be expanded (binomial theorem) into a finite sum of powers of ax. Then rearrange double sum to keep like powers of ax together.
 
mathman said:
By brute force: (ax+b)m+q can be expanded (binomial theorem) into a finite sum of powers of ax. Then rearrange double sum to keep like powers of ax together.

MANY THANKS FOR YOUR HELP.
HOWEVER, (ax+b)^(m+q) is the denominator of a fraction.
Could you please solve this again for me.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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