- #1
Xilor
- 152
- 7
Heya, I was wondering what happens when you measure the spin of particles along several different angles on an entangled pair.
As far as I understand Bell's theorem, it basically says that if you first measure particle A in some angle, and then measure a particle B at some some angle, you'll get a result at B that depends on which angle you chose at A. So if you picked a different angle A', we would have a different amount of expected correlations.
So measuring in this order:
AB
Gives different results at B than
A'B
Now I'm curious what happens if you measure A twice along different angles, in orders:
AA'B or A'AB
Out of these two, which of these would have the same results (on average) at B as measuring in order AB ? Is it one of them, both, neither? Or is this just a dumb question to begin with?
And as a follow up, if you do:
ABA'B or A'BAB does this end up giving you the same final result at B as the previous two orders?
How about ABB'B and AB'B? Are these the same as AB?
As far as I understand Bell's theorem, it basically says that if you first measure particle A in some angle, and then measure a particle B at some some angle, you'll get a result at B that depends on which angle you chose at A. So if you picked a different angle A', we would have a different amount of expected correlations.
So measuring in this order:
AB
Gives different results at B than
A'B
Now I'm curious what happens if you measure A twice along different angles, in orders:
AA'B or A'AB
Out of these two, which of these would have the same results (on average) at B as measuring in order AB ? Is it one of them, both, neither? Or is this just a dumb question to begin with?
And as a follow up, if you do:
ABA'B or A'BAB does this end up giving you the same final result at B as the previous two orders?
How about ABB'B and AB'B? Are these the same as AB?