I Measuring Low Resistance: Why Meter Bridge is the Preferred Choice

Click For Summary
The meter bridge is preferred over the post office box for measuring low resistance due to its superior sensitivity and accuracy. The post office box, which operates as a Wheatstone bridge, is limited in its measurement range and primarily used for identifying short circuits rather than measuring resistance. Its design does not effectively utilize the meter's sensitivity because it is affected by the bridge components. Additionally, the meter bridge allows for a more precise measurement technique by enabling current to pass through the meter for full-scale deflection before measuring the voltage drop across an unknown low resistance. Overall, the meter bridge is more effective for low resistance measurements compared to the post office box.
phymath7
Messages
48
Reaction score
4
TL;DR
Why post office box can't be used to measure high or low resistance?
Why meter bridge is chosen over post office box to measure low resistance?
 
Physics news on Phys.org
What is "post office box" (or "vox")?
 
Ah. According to the Wikipedia article the Post Office Box (origin UK) is in fact a Wheatstone bridge circuit.
 
phymath7 said:
TL;DR Summary: Why post office box can't be used to measure high or low resistance?

Why meter bridge is chosen over post office box to measure low resistance?
Who says it can't be used to measure high or low resistance ?
The post office box was two arms of a Wheatstone bridge.
It was used to find short circuits, not open breaks in the line.
 
phymath7 said:
TL;DR Summary: Why post office box can't be used to measure high or low resistance?

Why meter bridge is chosen over post office box to measure low resistance?
I think the measurement range will be limited by the available ratio arms and standard resistances. In addition, a bridge does not make best use of the meter sensitivity because it is shunted by the bridge components. There is a sensitive method for low resistances where we first pass a current through the meter to give full scale deflection and then measure the drop in reading when the meter is shunted by the unknown low resistance.
(Sorry, I recently disposed of my copy of "Telephony", by Herbert and Proctor, which would have given the definitive answer).
 
Thread 'Why higher speeds need more power if backward force is the same?'
Power = Force v Speed Power of my horse = 104kgx9.81m/s^2 x 0.732m/s = 1HP =746W Force/tension in rope stay the same if horse run at 0.73m/s or at 15m/s, so why then horse need to be more powerfull to pull at higher speed even if backward force at him(rope tension) stay the same? I understand that if I increase weight, it is hrader for horse to pull at higher speed because now is backward force increased, but don't understand why is harder to pull at higher speed if weight(backward force)...

Similar threads

  • · Replies 57 ·
2
Replies
57
Views
12K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
694
  • · Replies 2 ·
Replies
2
Views
584
  • · Replies 105 ·
4
Replies
105
Views
11K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 38 ·
2
Replies
38
Views
5K
Replies
16
Views
2K
Replies
8
Views
8K