Measuring Spin - wave function collapse

Click For Summary
SUMMARY

The discussion centers on the measurement of spin components in quantum mechanics, specifically the behavior of spin operators S_x, S_y, and S_z. It is established that measuring S_z followed by S_y results in a particle in an eigenstate of S_y, while measuring S_y followed by S_x yields an expectation value of zero for S_x. This is attributed to the nature of eigenstates and the preferred measurement direction, where S_z exhibits non-zero values in certain states. The distinction between measurement outcomes and expectation values is emphasized, clarifying that expectation values can be zero even when measurements yield definite results.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly spin operators.
  • Familiarity with eigenstates and their implications in quantum measurements.
  • Knowledge of expectation values in quantum systems.
  • Basic grasp of Stern-Gerlach experiments and their significance in demonstrating quantum behavior.
NEXT STEPS
  • Study the implications of measuring spin in quantum mechanics, focusing on S_x, S_y, and S_z operators.
  • Explore the concept of eigenstates in quantum mechanics and their role in measurement outcomes.
  • Learn about expectation values and their calculation in quantum systems.
  • Investigate the Stern-Gerlach experiment and its relevance to understanding spin measurements.
USEFUL FOR

Quantum physicists, students of quantum mechanics, and anyone interested in the measurement theory of spin in quantum systems.

benbenny
Messages
38
Reaction score
0
It is my understanding that a measurement of S_z followed by a measurement of S_y will result in a particle which is in an eigenstate of S_y. But it appears that a measurement of say S_y followed by a measurement of S_x results in zero. I see this from a question in which I am asked to find the expectation value of S_x for a particle in an eigenstate of S_y and my result is zero. But for S_z it is non zero.
I don't understand why this is so. Could someone help me understand why we find non zero S_z values but zero S_x values for a partilce in an S_y eigenstate.

Thanks in advance.

B
 
Physics news on Phys.org
Taking a measurement is not the same as finding the expectation value. If you take a measurement of Sx or Sz, you'll always get 1/2 or -1/2 (in units of h-bar). The expectation value is what you'd expect if you took many measurements and averaged the results.
 
vela said:
Taking a measurement is not the same as finding the expectation value. If you take a measurement of Sx or Sz, you'll always get 1/2 or -1/2 (in units of h-bar). The expectation value is what you'd expect if you took many measurements and averaged the results.

Ok. I understand now. Thank you Vela.

It makes sense that the expectation value in the S_z direction is NOT zero even if we are in a quantum state of S_x or S_y since it is the "preferred" direction I suppose, while S_x and S_y should exhibit zero expectation if we are in the S_z eigenstate as they sort of rotate around S_z.
or something like that. cheers.
 
If you're in an eigenstate of Sx, the preferred direction is along the x-axis. You should find the expectation values of Sy and Sz to be zero.

Keep in mind that x, y, and z are just labels we use to keep things straight. There's nothing intrinsically special about the z-axis.
 
vela said:
If you're in an eigenstate of Sx, the preferred direction is along the x-axis. You should find the expectation values of Sy and Sz to be zero.

Keep in mind that x, y, and z are just labels we use to keep things straight. There's nothing intrinsically special about the z-axis.

oh ok. now I think I really do understand. Source of confusion: hypothetical triple stern-gerlach experiment which exhibits that taking a measurement of Sx on an Sz eigenstate beam would produce 2 more beams in eigenstates of Sx. Obviously 2 resulting beams in the up and down eigenstates of Sx still amount to a zero expectation value.

Thanks again Vela, and if your interested in helping me with another unrelated question regarding GR and the cylinder condition that would be great as well : https://www.physicsforums.com/showthread.php?t=399738

cheers.

B
 

Similar threads

Replies
8
Views
6K
  • · Replies 24 ·
Replies
24
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
5K