[Mechanics] Calculate the braking torque

AI Thread Summary
The discussion revolves around calculating braking torque for a wheel in a braking system. The user initially struggles with dynamics equations, noting that the torque calculation using rotational acceleration yields zero due to constant speed. They explore an alternative formula for torque that incorporates friction and the radius of the wheel, which they suspect is missing from the problem statement. Another participant clarifies that the rotational speed should be considered as an initial speed, emphasizing the need to determine deceleration for accurate calculations. The user ultimately calculates a torque of approximately 39 N.m using an assumed radius and concludes that it takes four laps for the wheel to stop.
hugo_faurand
Messages
62
Reaction score
10
Homework Statement
We have a wheel spinning with a speed of 20rad/s.
The brake exerts a tangential force of 2073.6N and a normal force of 5760N.
(No radius given for the wheel)

1/Calculate the braking torque exerted by the braking force.

2/ Calculate how much rotations the wheel do before it stops

(3/ Which scaleswould be interesting to calculate ?)
Relevant Equations
Inertia of the wheel : 100m²/kg
μ=0.36
Hello ev
braking system.jpg
eryone !

I've got a problem in engineering class with a braking system (picture linked).
In the first part I calculated the friction force $$ \vec{B} $$ with components :
T (following y axis) : 2073.6N
N (following x axis) : 5760N.

For the first question I struggle a lot because I haven't seen dynamics equations yet.
But on the web I saw that we can calculate the braking torque C with the equation :
$$C= J \times \alpha $$ alpha is the rotational acceleration. But our wheel is spinning at a constant speed so $$\alpha=0$$ and thus C=0 and that's strange. I found another formula : $$C= n \times N \times \mu \times r $$ r stands for the radius of the wheel, n is the number of pair of frictionning surfaces here 1 and N the normal force acting on the wheel.

This one is interesting because although we don't have the radius (I think that's an error from my teacher) we'll have a non-zero value.

For the question 2/ I use the kinetic energy theorem that tells us that the work of the system is equal to the difference of kinetic energies. So we have $$W = \frac{1}{2} J \omega_2^2 - \frac{1}{2} J \omega_1^2 = \frac{1}{2} J (\omega_2^2-\omega_1^2)$$
Whereas $$W=J\times \theta $$ thus we have $$ \theta = \frac{W}{C} $$

Here is one solution for me and then we just have to divide the result by 2 pi to have the number of laps.

For the last question I've got no idea maybe the power...

So if you can help me because I'm not really sure of my work.
For the radius of the wheel maybe I can just take an arbitrary value, if the literal steps are good I think that's the most important.

Thx in advance
 
Physics news on Phys.org
One comment:
I think that the rotational speed is an initial speed, not a constant speed, as you state (##\alpha =0##). I say that because part of the problem is to determine when the wheel stops.
 
FactChecker said:
One comment:
I think that the rotational speed is an initial speed, not a constant speed, as you state (##\alpha =0##). I say that because part of the problem is to determine when the wheel stops.
That's right but we have no statement about the duration of the braking. So we can't determine the deceleration.
 
hugo_faurand said:
we can calculate the braking torque ##C## with the equation :$$C=J\times\alpha$$
Conversely, if we know ##C##, we can calculate the deceleration rate !

(assume you are right about '(I think that's an error from my teacher) ' and use the symbol ##r## )
 
Last edited:
I made all the calculations with a radius of 53mm and I've a torque of almost 39 N.m and it needs 4laps to stop. Is it coherent ?

(Otherwise spend good end of the year festivities !)
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top