Mechanics, degree of freedom question

AI Thread Summary
The discussion revolves around calculating the degrees of freedom (DoF) for a mechanical system using the formula M = 3(L-1) - 2J1 - J2. The user is confident in identifying 9 links and 1 half-joint but is uncertain about the number of full binary joints, particularly regarding the slider mechanism. There is confusion about whether to count two binary joints for the slider or consider them as a single ternary joint. The user concludes that there may only be 1 DoF related to the rotational movement of a circle at the top of the system. The conversation also touches on the implications of multiple strings meeting at a point and their potential configurations.
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Homework Statement



Calculate the DoF (mobility) of the following system:

3026041de8b9529d84160ec6964b3ec4.png


Homework Equations


[/B]
M = 3(L-1) - 2J1 - J2

(where L = number of links, J1 is the number of full binary joints and J2 is the number of half joints.

The Attempt at a Solution



I am very confident about there being 9 links, and 1 half-joint (the pin in the slot above the L link) but I am unsure about the number of full joints which I numbered here.

2b60e7e0a8424c6c6a8b32d4ec9c2d8a.png


I know from 1-7 should be correct, but I don't know about the joints on the slider. Should there only be two binary joints for each like I put there? Which is basically one ternary joint... 2 on the rigid link 'L' and on the link to which the slider is attached.

And if I am correct I take it there is only 1 DoF then, which is the rotational of the circle attached to the top?

Help would be appreciated here.
 
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