1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Mechanics of Materials Torsion Test Help

  1. Oct 27, 2009 #1
    1. The problem statement, all variables and given/known dataHello, I am writing up a lab for a torsion test that we performed on mild steel (ductile material) and cast iron (brittle material). For each of the materials, we must find:
    • For Mild Steel:
    - Torque vs. Angle of Twist per unit length.
    - Shear Modulus
    - Shear Yield Strength
    - Torque Modulus of Resilience
    - Torque Modulus of Toughness
    - Limit Shear Stain
    • For Cast Iron:
    - Torque vs. Angle of Twist per unit length.
    - Shear Modulus
    - Modulus of Rupture
    - Limit Shear Stain

    2. Relevant equations
    Ip = Polar MoI
    We are using Shear Stress(tau)= Torsion*radius/Ip
    and Shear Strain (gamma) = phi*radius/L

    3. The attempt at a solution
    This may be relativly simple to answer. For both materials I have an excel spread sheet with data from the lab. They gave me Torque and Twist angle, and from those two tables, I was able to create a second data set for Shear stress and strain. I put these tables in to graphs and have a graph that looks similar to this for my cast Iron:
    I know shear modulus, or G, is just the slope of the line for the plastic behavioral part of the material. The modulus of rupture is defined in my lab as the shear stress calculated from the maximum torque found during the test. So It will just be my shear stress value at the very end of the graph (correct me if im wrong). Then I come to the Limit shear strain and get confused. Is this the same as the modulus of rupture? It seems silly they would ask for two values which essentially mean the same thing. Do you know if this is another term for yield limit? if thats the case, then there should technically be none since it is a brittle material (please let me know if I am wrong here). Any Ideas or clarification will help.
  2. jcsd
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted