Mechanics potential energy problem

The equilibrium angle is the angle at which the potential energy is at its minimum, meaning that the forces acting on the pendulum are balanced. This can be found by setting the derivative of the potential energy with respect to angle equal to zero. In this case, there is only one equilibrium angle, which can be found by setting the tangential component of the electric force equal to the gravitational force. For part 3), the work done by the electric field can be found by integrating the electric force over the displacement of the pendulum. This can be done by considering the change in potential energy of the system as the pendulum moves from θs-θo to θs+θo. So far, we have found the potential
  • #1
osamapw1nladen
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A small ball of mass M carries a positive charge Q. The ball is glued to the end of a massless stick of length L. The other end of the stick is attached to a frictionless pivot that allows the pendulum to swing in the xy plane. Gravity is in the minus y direction. A constant electric field Eº points in the positive x direction.
1) Find a potential energy as a function of angle θ and find an expression for the equilibrium angle(s). How many are there? Explain
2) Find the angular frequency, ωo, of small oscillations about the stable equilibrium angle, θs.
3) Assume that the pendulum is ocsillating with aplitude θo-θs. Find the work done by the electric field as the pendulum moves from θs-θo to θs+θo.
 
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  • #2
What have you done so far to solve the problem?
 
  • #3
absolutely nothing, i have no clue how to even start the problem
 
  • #4
Begin by finding all forces that apply to the system
 
  • #5
the only thing i got is that there's a force acting in the positive x-direction from the electric field, and a force in the negative y-direction from gravity. i don't know how to find where the acceleration would be
 
  • #6
I will give you solution to the part 1)
The potential energy of the system

[tex]W=mgl(1-\cos\theta)-QEl\sin\theta[/tex]

where the origine of poential energy is at the lowest point of the mass
The system gets the equilibrium state when

[tex]\frac{dW}{d\theta}=0\Longrightarrow tan\theta=\frac{mg}{QE}[/tex]

Now, continue ...
 
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  • #7
For part 2), because the amplitude of oscillation is small, so we can use

[tex]1-cos\theta=2\sin^2\frac{\theta}{2}=\frac{1}{2}\theta^2[/tex]

then using the law of conservation of energy.
 
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1. What is potential energy in mechanics?

Potential energy in mechanics is the energy that an object possesses due to its position or configuration. It is stored energy that can be converted into other forms of energy, such as kinetic energy, when the object is in motion.

2. How is potential energy calculated in mechanics?

Potential energy in mechanics is calculated using the equation PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above a reference point.

3. What is the difference between gravitational potential energy and elastic potential energy?

Gravitational potential energy is the energy an object has due to its position in a gravitational field, while elastic potential energy is the energy stored in an object when it is stretched or compressed. Gravitational potential energy is related to the force of gravity, while elastic potential energy is related to the force of elasticity.

4. How can potential energy be converted into kinetic energy?

Potential energy can be converted into kinetic energy when an object is allowed to move freely from a higher position to a lower position. As the object falls, its potential energy decreases and its kinetic energy increases.

5. Why is potential energy important in mechanics?

Potential energy is important in mechanics because it is a fundamental concept that helps us understand the behavior of objects and systems. It allows us to analyze and predict the motion of objects, and it is a key component in the law of conservation of energy, which states that energy cannot be created or destroyed, only converted from one form to another.

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