# Homework Help: Melting ice

1. Nov 30, 2006

1. The problem statement, all variables and given/known data
How much energy is necessary to completely melt an ice cube of mass 360.6grams that is initially at a temp of -25.2 degrees celsius.

2. Relevant equations
im thinkin i should use specific heat equation? is that right?
c=Q/m(change of temp)
2090=Q/.36069(25.2)

3. The attempt at a solution
Q= 18992
i kno its wrong but im not sure what approach i need to take in finding the correct answer.

2. Nov 30, 2006

3. Nov 30, 2006

### Gokul43201

Staff Emeritus
You've done one part of the calculation. You've found the energy it takes to heat the ice from -25.2C to 0C, but it's still ice at 0C. You now need to convert this ice into water. How much energy does it take to do that?

Look up the what the term 'Latent Heat' means.

4. Nov 30, 2006

ahhh ok.. i knew i missed sumthin important

so ... .3606x25.2x2090= 18992.0808
then i use the latent heat of fusion for water and get .3606x(33.5x10^5)=120801

combine them 18992.0808+120801= 139793.0808 --> 1.4x10^5

thank you gokul