Membranes, proton pump/ cotransport

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Diarrhea patients receive solutions with high concentrations of glucose and salt to create hypertonic conditions in the blood, which promotes water absorption from the intestines through osmosis. This process helps to replenish lost fluids and electrolytes. The discussion also touches on the role of ADH (anti-diuretic hormone), noting that while its levels decrease, it is not directly related to the treatment for diarrhea. The glucose in the solution aids in enhancing sodium absorption, which further helps in fluid retention. Overall, the combination of glucose and salt is crucial for effective rehydration in diarrhea cases.
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Homework Statement



Why do diarrhea patients receive a solution containing a high concentration of glucose and salt?
 
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By creating hypertonic conditions in the blood, water moves out of the intestines due to osmosis. ADH (anti-diuretic hormone) levels also sink and the permeability of the walls of the urethra decreases causing less water to be lost.
 
Yousef said:
ADH (anti-diuretic hormone) levels also sink and the permeability of the walls of the urethra decreases causing less water to be lost.
false statement.

But what effect does the glucose have?
 
Ok, thing with ADH is true but unrelated to what we're doing, I was just messing with you.
Seriously now though, look at the solutions to Bac 2002 Question P2 a).
It has your glucose problem.
:approve:
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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