Merry go round, rotational dynamics

AI Thread Summary
To find the new angular speed of a merry-go-round after a child hops on, the moment of inertia for the child should be calculated using I = mr², treating the child as a point mass. The initial moment of inertia of the merry-go-round is given as I1 = 250 kg/m², and the initial angular speed is 10 rpm. The equation I1w1 = (I1 + I2)w2 can be used to solve for the new angular speed w2 after the child, with a mass of 25 kg, joins. The confusion about using I = 1/2mr² for the child is clarified, as this formula applies to solid objects rather than point masses. The discussion emphasizes the importance of correctly applying the moment of inertia formulas based on the object's characteristics.
pb23me
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Homework Statement


A plyground merry go round of radius r=2m had a moment of inertia of I=250kg/m2 and is rotating at 10rpm about a frictionless verticle axle.Facing the axle a 25kg child hops onto the merry go round and manages to sit down on its edge.What is the new angular speed of the merry go round?


Homework Equations


I1w1=(I1+I2)w2


The Attempt at a Solution

The problem seems really easy i just plug in the values i have and get two unknowns. The only problem is i don't know what the value of I is for the child? Am i supposed to calculate this somehow? Or just use the value of I = 1/2mr2 that is for a solid cylinder?
 
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The idea is to treat the child as a point particle.
 
now that wouldn't be very nice:mad::biggrin:
ok but i still don't know how to obtain the value of I for the kid... is it just mr2
or do i use I that is for a solid cylinder I=1/2(mr2)?
 
pb23me said:
now that wouldn't be very nice:mad::biggrin:
ok but i still don't know how to obtain the value of I for the kid... is it just mr2
or do i use I that is for a solid cylinder I=1/2(mr2)?
The moment of inertia of a point particle is I = mr2, so that is what you should use. Why do you think that you should use the moment of inertia of a cylinder?
 
well, because my lab book says "The moment of inertia is given mathematically by \Sigmamr2... so yes it seems like the moment of inertia is mr2,however when i look at all the moment of inertias for different objects solid sphere I=2/5mr2, solid cylinder 1/2mr2 and so on... where does the 2/5 and 1/2 come from? Thats why i was thinking you just can't say the moment of inertia is mr2
 
pb23me said:
well, because my lab book says "The moment of inertia is given mathematically by \Sigmamr2... so yes it seems like the moment of inertia is mr2,however when i look at all the moment of inertias for different objects solid sphere I=2/5mr2, solid cylinder 1/2mr2 and so on... where does the 2/5 and 1/2 come from? Thats why i was thinking you just can't say the moment of inertia is mr2
For objects other than point masses, you need to sum the moment of inertia of all the individual point masses in that object in order to determine the overall moment inertia. In practise this is done through integrals. See here for more information: http://hyperphysics.phy-astr.gsu.edu/hbase/mi.html

However, for the question in hand, it is perfectly reasonable to treat the child as a point mass.
 
ok that makes sense, thanx
 
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