Merry-go-round + sphere tied to rod

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To find the angular velocity of the merry-go-round, apply Newton's second law to the forces acting on the suspended sphere. The problem involves analyzing the tension in the string and the gravitational force on the sphere. A free body diagram should be drawn to visualize these forces, which include the weight of the sphere and the tension acting at an angle. The key is to determine the acceleration of the sphere, which relates to the angular velocity of the merry-go-round. By solving these equations, the angular velocity can be calculated effectively.
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Homework Statement



A small 0.160 kg sphere is suspended by a light string from a vertical post mounted at the edge of a merry-go-round of radius R = 0.440 m.
The equilibrium position of the sphere is shown in the figure, with a = 0.430 m and b = 0.760 m. The axis of rotation is indicated by the dashed line. Calculate the angular velocity of the merry-go-round.

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The Attempt at a Solution



This is where I'm getting stuck. I can't figure out where to start. I have an idea that this problem deals with Newton's 2nd law, but I don't know how to apply it this situation.

Would using the torque equation help?: \tau = F * r * sin\theta
 
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Follow standard procedure: Draw a free body diagram of the sphere, showing all the forces acting on it. (Hint: There are only two forces.) Key: What's the acceleration of the sphere? Then apply Newton's 2nd law.

(No need for torques.)
 
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