Mesh analysis, 2 meshes 1 known current source

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SUMMARY

The forum discussion centers on calculating the current i1 in a mesh analysis problem involving two meshes and a known current source. Given the parameters Vs=10V, I=1A, R1=5Ω, R2=2Ω, and R3=4Ω, the correct calculation using Kirchhoff's Voltage Law (KVL) yields i1=1.56A. However, the textbook states the answer as 1.71A, which participants in the discussion agree is likely a book error, as their calculations consistently support the 1.56A result.

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mishima
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Homework Statement


Find i1 in the following figure, given: Vs=10V, I=1A, R1=5, R2=2, R3=4

prob.jpg


Homework Equations


KVL


The Attempt at a Solution


Applying KVL to mesh 1:
Vs-i1R1-(i1-i2)R3=0
and i2=I=1A
So,
i1=(Vs+i2R3)/(R1+R3)=(10+1*4)/(5+4)=14/9=1.56 A

But book gives answer as 1.71 A.
 
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I also get the same answer when doing node analysis. I think this is just a book error, not in the errata.
 
mishima said:
I also get the same answer when doing node analysis. I think this is just a book error, not in the errata.


Looks like a book error; I agree with your result.
 

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