[tex]\frac{dv}{dt}= -x^{-3}[/tex](adsbygoogle = window.adsbygoogle || []).push({});

when t=0, the particle is at rest with x=1

Therefore by integrating i get

[tex]v = \sqrt(x^-2 - 1)[/tex]

[tex]\frac{dx}{dt}= \sqrt(\frac{1 - x^2}{x^2})[/tex]

[tex]dx\frac{x}{(/sqrt(1 - x^2))} = dt[/tex]

[tex]-\sqrt(1 - x^2) = t + C[/tex]

[tex]C=-1[/tex]

Therefore:-

[tex]t = 1 - \sqrt(1 - x^2)[/tex]

However i cant get the answer [tex]t = \sqrt(15)[/tex] when [tex]x = 1/4[/tex]. I think i messed up somewhere in my integration. I would really appreciate any help with this.

Thank you,

Bob

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# Homework Help: Messed up somewhere in my integration

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