Meteor Accelerating towards the Earth

AI Thread Summary
The discussion centers on calculating the height of a meteor above the Earth's surface, given its mass and acceleration due to gravity. Using the formula r=√(G*ME/g), the calculated distance from the center of the Earth is approximately 7.4 million meters. Subtracting the Earth's radius results in a height of about 1.06 million meters, or 1060 km, above the surface. A key point raised is that the mass of the meteor is unnecessary for this calculation. Overall, the solution appears to be correct, confirming the calculations made.
HarleyM
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Homework Statement



a 12 kg meteor experiences an acceleration of 7.2 m/s^2, when faling towards the earth.

How high above the Earths surface is the meteor?


Homework Equations


mass of earth= 5.98x1024 kg
radius of earth= 6.36x106 m

g=G*MEarth/r2

r=√G*ME/g



The Attempt at a Solution



r=√G*ME/g
=√(6.67x10-11)(5.98x1024)/(7.2)
=7.4x106 m

7.4x106-6.36x106
=1.06 x106 m above the Earths surface, or 1060 km?

Does everything look good? Thanks in advance for any help!
 
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This looks OK.
Did you realize you did not need the mass of the meteor in the calculation??
 
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