Meter stick and rock balancing ?

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In the scenario of a meter stick supported at the 25-cm mark with a 1-kg rock at the 0-cm end, the stick is in equilibrium, indicating that the torques around the pivot point are balanced. The mass of the meter stick must be less than the mass of the rock to maintain this equilibrium, as the rock creates a greater torque due to its distance from the pivot. An extended free body diagram would illustrate the forces acting on the meter stick, including the weight of the rock and the gravitational force on the meter stick itself. Participants emphasize the importance of demonstrating understanding before seeking assistance. The discussion highlights the principles of torque and equilibrium in physics.
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A uniform meter stick supported at the 25-cm mark is in equilibrium when a 1-kg rock is suspended at the 0-cm end. Is the mass of the meter stick greater than, equal to, or less than the mass of the rock? Explain your reasoning.

Thanks in advance for any help!
 
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Can you draw an extended free body diagram for the situation?
 
I see you're fairly new, but you have to show that you tried before you get any help.
 
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